Major Grade E-Port.

Derrick Boyd

12-06-18

4th period

 On this particular problem I’m solving for a this is a Pythagorean theorem.First I squared 13 and 17. I got 169 and 289 I subtracted both by 169. I cancelled out 169 subtracted 169 cause it equals zero. So when i subtracted 169 by 289 I got 120 so now I have square a and 120. And what i got for answer is a=10.955.

 On this i have to find x by using trig ratios. First i start with tangent and the tangent i put opposite over adjacent so that means 18 goes over x. And 67 goes in parentheses behind tangent that’s how i get 2.356. Now i multiply  2.256x by 2.256 and 18 divided by 2.256. 2.256x is cancelled cause that by 2.256 gives you zero. So i got from 18 divided by 2.256 is 7.979 and that’s how I got x.

On this problem i solved for tangent too and like i said in the last problem opposite goes over adjacent. This 15 goes behind tangent and 22 goes x. From putting 15 behind tangent i got 0.268 and i multiplied that and 18 by x. so now i multiply 0.268x by 0.268 i cancelled it cause it gives you zero.  and now on the back which is the picture the below i divided 22 by 0.268 and my x answer 82.080.

 On this inverse trig ratios problem have to solved with sine. And for sine it’s opposite over hypotenuse. So that means 18 goes 25 then you divide that and you 0.72. So you use inverse to get your answer. And the answer will 46.054 and you 0.72 into inversed sine.